Мне нужно запустить запрос против старой таблицы, в которой хранится URL-код. Мне нужно, чтобы этот текст был расшифрован в моих результатах. Как достичь этого?
Декодирование URL-адресов SQL Server
Ответ 1
Попробуйте выполнить одно из следующих действий:
CREATE FUNCTION dbo.UrlDecode(@url varchar(3072))
RETURNS varchar(3072)
AS
BEGIN
DECLARE @count int, @c char(1), @cenc char(2), @i int, @urlReturn varchar(3072)
SET @count = Len(@url)
SET @i = 1
SET @urlReturn = ''
WHILE (@i <= @count)
BEGIN
SET @c = substring(@url, @i, 1)
IF @c LIKE '[!%]' ESCAPE '!'
BEGIN
SET @cenc = substring(@url, @i + 1, 2)
SET @c = CHAR(CASE WHEN SUBSTRING(@cenc, 1, 1) LIKE '[0-9]'
THEN CAST(SUBSTRING(@cenc, 1, 1) as int)
ELSE CAST(ASCII(UPPER(SUBSTRING(@cenc, 1, 1)))-55 as int)
END * 16 +
CASE WHEN SUBSTRING(@cenc, 2, 1) LIKE '[0-9]'
THEN CAST(SUBSTRING(@cenc, 2, 1) as int)
ELSE CAST(ASCII(UPPER(SUBSTRING(@cenc, 2, 1)))-55 as int)
END)
SET @urlReturn = @urlReturn + @c
SET @i = @i + 2
END
ELSE
BEGIN
SET @urlReturn = @urlReturn + @c
END
SET @i = @i +1
END
RETURN @urlReturn
END
GO
из http://sqlblog.com/blogs/peter_debetta/archive/2007/03/09/t-sql-urldecode.aspx
CREATE FUNCTION dbo.fnDeURL
(
@URL VARCHAR(8000)
)
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE @Position INT,
@Base CHAR(16),
@High TINYINT,
@Low TINYINT,
@Pattern CHAR(21)
SELECT @Base = '0123456789abcdef',
@Pattern = '%[%][0-9a-f][0-9a-f]%',
@URL = REPLACE(@URL, '+', ' '),
@Position = PATINDEX(@Pattern, @URL)
WHILE @Position > 0
SELECT @High = CHARINDEX(SUBSTRING(@URL, @Position + 1, 1), @Base COLLATE Latin1_General_CI_AS),
@Low = CHARINDEX(SUBSTRING(@URL, @Position + 2, 1), @Base COLLATE Latin1_General_CI_AS),
@URL = STUFF(@URL, @Position, 3, CHAR(16 * @High + @Low - 17)),
@Position = PATINDEX(@Pattern, @URL)
RETURN @URL
END
Ответ 2
create function [dbo].[URLDecode](
@str nvarchar( max )
) returns nvarchar( max )
begin
if @str is null return null
declare @out nvarchar( max ) = N''
set @str = replace( @str, N'+', N'%20' )
while len(@str) > 0
begin
declare @i bigint = patindex( N'%[%][0-9a-fA-F][0-9a-fA-F]%', @str )
if @i = 0 break
set @out = @out + substring( @str, 0, @i ) + convert( nchar(2), convert( varbinary, '0x' + substring( @str, @i + 1, 2 ), 1 ) )
set @str = substring( @str, @i + 3, len(@str) )
end
return @out + @str
end
Ответ 3
Код для меня не работает.... Здесь мой код:
create function [UrlDecode](@url nvarchar(max))
returns nvarchar(max)
as
begin
declare @output nvarchar(max), @C nvarchar(255), @C1 nvarchar(255), @C2 nvarchar(255), @IsUrl int
set @output = ''
declare @T table(I int identity(1,1), C nvarchar(255))
insert @T(C)
select items from dbo.Split(@url,'%')
set @IsUrl = charindex('%', @url)
declare cur cursor for select C from @T order by I
open cur
fetch next from cur into @C
while @@fetch_status = 0 begin
set @C1 = substring(@C, 2, 4)
set @C2 = substring(@C, 6, 255)
if substring(@C, 1, 1) = 'u' and @IsUrl <> 0 begin
if @C1 is not null
set @output = @output + char((CONVERT(INT,CONVERT(VARBINARY(4),@C1,2)))-1264)
if @C2 is not null
set @output = @output + @C2
end else begin
set @output = @output + isnull(substring(@C, 1, 255),'')
end
fetch next from cur into @C
end
close cur
deallocate cur
return @output
end`
Функция "Разделить":
create function [Split](@String nvarchar(max), @Delimiter char(1))
returns @temptable table (items nvarchar(max))
as
begin
set @String = ltrim(rtrim(@String))
declare @idx int
declare @slice nvarchar(max)
select @idx = 1
if len(@String)<1 or @String is null return
while @idx!= 0
begin
set @idx = charindex(@Delimiter,@String)
if @idx!=0
set @slice = left(@String,@idx - 1)
else
set @slice = @String
if(len(@slice)>0)
insert into @temptable(Items) values(@slice)
set @String = right(@String,len(@String) - @idx)
if len(@String) = 0 break
end
return
end
Ответ 4
Если вам нужно решение, которое поддерживает не английские символы (юникод), есть отличный пример на CodeProject:
CREATE FUNCTION [dbo].[UrlDecode] (
@URL NVARCHAR(4000) ) RETURNS NVARCHAR(4000) AS BEGIN
DECLARE @Position INT, @Base CHAR(16), @High TINYINT, @Low TINYINT, @Pattern CHAR(21)
DECLARE @Byte1Value INT, @SurrogateHign INT, @SurrogateLow INT
SELECT @Pattern = '%[%][0-9a-f][0-9a-f]%', @Position = PATINDEX(@Pattern, @URL)
WHILE @Position > 0
BEGIN
SELECT @High = ASCII(UPPER(SUBSTRING(@URL, @Position + 1, 1))) - 48,
@Low = ASCII(UPPER(SUBSTRING(@URL, @Position + 2, 1))) - 48,
@High = @High / 17 * 10 + @High % 17,
@Low = @Low / 17 * 10 + @Low % 17,
@Byte1Value = 16 * @High + @Low
IF @Byte1Value < 128 --1-byte UTF-8
SELECT @URL = STUFF(@URL, @Position, 3, NCHAR(@Byte1Value)),
@Position = PATINDEX(@Pattern, @URL)
ELSE IF @Byte1Value >= 192 AND @Byte1Value < 224 AND @Position > 0 --2-byte UTF-8
BEGIN
SELECT @Byte1Value = (@Byte1Value & (POWER(2,5) - 1)) * POWER(2,6),
@URL = STUFF(@URL, @Position, 3, ''),
@Position = PATINDEX(@Pattern, @URL)
IF @Position > 0
SELECT @High = ASCII(UPPER(SUBSTRING(@URL, @Position + 1, 1))) - 48,
@Low = ASCII(UPPER(SUBSTRING(@URL, @Position + 2, 1))) - 48,
@High = @High / 17 * 10 + @High % 17,
@Low = @Low / 17 * 10 + @Low % 17,
@Byte1Value = @Byte1Value + ((16 * @High + @Low) & (POWER(2,6) - 1)),
@URL = STUFF(@URL, @Position, 3, NCHAR(@Byte1Value)),
@Position = PATINDEX(@Pattern, @URL)
END
ELSE IF @Byte1Value >= 224 AND @Byte1Value < 240 AND @Position > 0 --3-byte UTF-8
BEGIN
SELECT @Byte1Value = (@Byte1Value & (POWER(2,4) - 1)) * POWER(2,12),
@URL = STUFF(@URL, @Position, 3, ''),
@Position = PATINDEX(@Pattern, @URL)
IF @Position > 0
SELECT @High = ASCII(UPPER(SUBSTRING(@URL, @Position + 1, 1))) - 48,
@Low = ASCII(UPPER(SUBSTRING(@URL, @Position + 2, 1))) - 48,
@High = @High / 17 * 10 + @High % 17,
@Low = @Low / 17 * 10 + @Low % 17,
@Byte1Value = @Byte1Value + ((16 * @High + @Low) & (POWER(2,6) - 1)) * POWER(2,6),
@URL = STUFF(@URL, @Position, 3, ''),
@Position = PATINDEX(@Pattern, @URL)
IF @Position > 0
SELECT @High = ASCII(UPPER(SUBSTRING(@URL, @Position + 1, 1))) - 48,
@Low = ASCII(UPPER(SUBSTRING(@URL, @Position + 2, 1))) - 48,
@High = @High / 17 * 10 + @High % 17,
@Low = @Low / 17 * 10 + @Low % 17,
@Byte1Value = @Byte1Value + ((16 * @High + @Low) & (POWER(2,6) - 1)),
@URL = STUFF(@URL, @Position, 3, NCHAR(@Byte1Value)),
@Position = PATINDEX(@Pattern, @URL)
END
ELSE IF @Byte1Value >= 240 AND @Position > 0 --4-byte UTF-8
BEGIN
SELECT @Byte1Value = (@Byte1Value & (POWER(2,3) - 1)) * POWER(2,18),
@URL = STUFF(@URL, @Position, 3, ''),
@Position = PATINDEX(@Pattern, @URL)
IF @Position > 0
SELECT @High = ASCII(UPPER(SUBSTRING(@URL, @Position + 1, 1))) - 48,
@Low = ASCII(UPPER(SUBSTRING(@URL, @Position + 2, 1))) - 48,
@High = @High / 17 * 10 + @High % 17,
@Low = @Low / 17 * 10 + @Low % 17,
@Byte1Value = @Byte1Value + ((16 * @High + @Low) & (POWER(2,6) - 1)) * POWER(2,12),
@URL = STUFF(@URL, @Position, 3, ''),
@Position = PATINDEX(@Pattern, @URL)
IF @Position > 0
SELECT @High = ASCII(UPPER(SUBSTRING(@URL, @Position + 1, 1))) - 48,
@Low = ASCII(UPPER(SUBSTRING(@URL, @Position + 2, 1))) - 48,
@High = @High / 17 * 10 + @High % 17,
@Low = @Low / 17 * 10 + @Low % 17,
@Byte1Value = @Byte1Value + ((16 * @High + @Low) & (POWER(2,6) - 1)) * POWER(2,6),
@URL = STUFF(@URL, @Position, 3, ''),
@Position = PATINDEX(@Pattern, @URL)
IF @Position > 0
BEGIN
SELECT @High = ASCII(UPPER(SUBSTRING(@URL, @Position + 1, 1))) - 48,
@Low = ASCII(UPPER(SUBSTRING(@URL, @Position + 2, 1))) - 48,
@High = @High / 17 * 10 + @High % 17,
@Low = @Low / 17 * 10 + @Low % 17,
@Byte1Value = @Byte1Value + ((16 * @High + @Low) & (POWER(2,6) - 1))
--,@URL = STUFF(@URL, @Position, 3, cast(@Byte1Value as varchar))
--,@Position = PATINDEX(@Pattern, @URL)
SELECT @SurrogateHign = ((@Byte1Value - POWER(16,4)) & (POWER(2,20) - 1)) / POWER(2,10) + 13 * POWER(16,3) + 8 * POWER(16,2),
@SurrogateLow = ((@Byte1Value - POWER(16,4)) & (POWER(2,10) - 1)) + 13 * POWER(16,3) + 12 * POWER(16,2),
@URL = STUFF(@URL, @Position, 3, NCHAR(@SurrogateHign) + NCHAR(@SurrogateLow)),
@Position = PATINDEX(@Pattern, @URL)
END
END
END
RETURN REPLACE(@URL, '+', ' ') END
Ответ 5
Я бы добавил немного дополнительного декодирования. Одна ошибка, с которой я столкнулся, - возвращаемое значение, было нулем. Я также заметил, что некоторые из приведенных выше ответов заменили знак "+" на пробел.
ALTER FUNCTION UrlDecode(@url varchar(3072))
RETURNS varchar(3072)
AS BEGIN
DECLARE @count int,
@c char(1),
@cenc char(2),
@i int,
@urlReturn varchar(3072)
SET @count = Len(@url)
SET @i = 1
SET @urlReturn = ''
WHILE (@i <= @count) BEGIN
SET @c = substring(@url, @i, 1)
IF @c LIKE '[!%]' ESCAPE '!' BEGIN
SET @cenc = substring(@url, @i + 1, 2)
SET @c = CHAR(CASE WHEN SUBSTRING(@cenc, 1, 1) LIKE '[0-9]'
THEN CAST(SUBSTRING(@cenc, 1, 1) as int)
ELSE CAST(ASCII(UPPER(SUBSTRING(@cenc, 1, 1)))-55 as int)
END * 16 +
CASE WHEN SUBSTRING(@cenc, 2, 1) LIKE '[0-9]'
THEN CAST(SUBSTRING(@cenc, 2, 1) as int)
ELSE CAST(ASCII(UPPER(SUBSTRING(@cenc, 2, 1)))-55 as int)
END)
SET @urlReturn = @urlReturn + @c
SET @i = @i + 2
END ELSE BEGIN
SET @urlReturn = @urlReturn + @c
END
SET @i = @i +1
END
IF @urlReturn is null BEGIN
set @urlReturn = ''
END ELSE BEGIN
set @urlReturn = REPLACE(@urlReturn, '+', ' ')
END
RETURN @urlReturn
END
GO