У меня есть текстовое поле, в которое пользователь вводит данные. Это поле номера телефона. Если пользователь вводит 1234567890, я хочу, чтобы он отображался как (123)-(456)-7890 по типу пользователя. Как это возможно?
Форматирование номера телефона
Ответ 1
Это поможет вам
Формат (xxx) xxx-xxxx
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
int length = (int)[self getLength:textField.text];
//NSLog(@"Length = %d ",length);
if(length == 10)
{
if(range.length == 0)
return NO;
}
if(length == 3)
{
NSString *num = [self formatNumber:textField.text];
textField.text = [NSString stringWithFormat:@"(%@) ",num];
if(range.length > 0)
textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:3]];
}
else if(length == 6)
{
NSString *num = [self formatNumber:textField.text];
//NSLog(@"%@",[num substringToIndex:3]);
//NSLog(@"%@",[num substringFromIndex:3]);
textField.text = [NSString stringWithFormat:@"(%@) %@-",[num substringToIndex:3],[num substringFromIndex:3]];
if(range.length > 0)
textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
}
return YES;
}
- (NSString *)formatNumber:(NSString *)mobileNumber
{
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
NSLog(@"%@", mobileNumber);
int length = (int)[mobileNumber length];
if(length > 10)
{
mobileNumber = [mobileNumber substringFromIndex: length-10];
NSLog(@"%@", mobileNumber);
}
return mobileNumber;
}
- (int)getLength:(NSString *)mobileNumber
{
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
int length = (int)[mobileNumber length];
return length;
}
Ответ 2
Это стало более ясным и более легко удаляет любые нежелательные персонажи. Правильно формируется для 1 (###) ### - #### или (###) ### - ####
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
NSString *newString = [textField.text stringByReplacingCharactersInRange:range withString:string];
NSArray *components = [newString componentsSeparatedByCharactersInSet:[[NSCharacterSet decimalDigitCharacterSet] invertedSet]];
NSString *decimalString = [components componentsJoinedByString:@""];
NSUInteger length = decimalString.length;
BOOL hasLeadingOne = length > 0 && [decimalString characterAtIndex:0] == '1';
if (length == 0 || (length > 10 && !hasLeadingOne) || (length > 11)) {
textField.text = decimalString;
return NO;
}
NSUInteger index = 0;
NSMutableString *formattedString = [NSMutableString string];
if (hasLeadingOne) {
[formattedString appendString:@"1 "];
index += 1;
}
if (length - index > 3) {
NSString *areaCode = [decimalString substringWithRange:NSMakeRange(index, 3)];
[formattedString appendFormat:@"(%@) ",areaCode];
index += 3;
}
if (length - index > 3) {
NSString *prefix = [decimalString substringWithRange:NSMakeRange(index, 3)];
[formattedString appendFormat:@"%@-",prefix];
index += 3;
}
NSString *remainder = [decimalString substringFromIndex:index];
[formattedString appendString:remainder];
textField.text = formattedString;
return NO;
}
Ответ 3
Ниже приведен код, который я обычно использую. Формат отличается, но вы получаете изображение. Это будет обрабатывать входные данные, такие как "123df # [email protected]$gdfg45- + 678dfg901" и вывод '1 (234) 567-8901'
#import "NSString+phoneNumber.h"
@implementation NSString (phoneNumber)
-(NSString*) phoneNumber{
static NSCharacterSet* set = nil;
if (set == nil){
set = [[NSCharacterSet decimalDigitCharacterSet] invertedSet];
}
NSString* phoneString = [[self componentsSeparatedByCharactersInSet:set] componentsJoinedByString:@""];
switch (phoneString.length) {
case 7: return [NSString stringWithFormat:@"%@-%@", [phoneString substringToIndex:3], [phoneString substringFromIndex:3]];
case 10: return [NSString stringWithFormat:@"(%@) %@-%@", [phoneString substringToIndex:3], [phoneString substringWithRange:NSMakeRange(3, 3)],[phoneString substringFromIndex:6]];
case 11: return [NSString stringWithFormat:@"%@ (%@) %@-%@", [phoneString substringToIndex:1], [phoneString substringWithRange:NSMakeRange(1, 3)], [phoneString substringWithRange:NSMakeRange(4, 3)], [phoneString substringFromIndex:7]];
case 12: return [NSString stringWithFormat:@"+%@ (%@) %@-%@", [phoneString substringToIndex:2], [phoneString substringWithRange:NSMakeRange(2, 3)], [phoneString substringWithRange:NSMakeRange(5, 3)], [phoneString substringFromIndex:8]];
default: return nil;
}
}
@end
Ответ 4
Мы записали пользовательский подкласс NSFormatter для телефонных номеров здесь: https://github.com/edgecase/PhoneNumberFormatter
Вы можете использовать его, как и любой другой подкласс NSFormatter.
Ответ 5
Большое спасибо за первый ответ, но, я думаю, этот метод -(int)getLength:(NSString*)mobileNumber бесполезен. Вы можете попробовать что-то вроде ниже:
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{
int length = [[self formatNumber:[textField text]] length];
if (length == 10) {
if(range.length == 0) {
return NO;
}
}
if (length == 3) {
NSString *num = [self formatNumber:[textField text]];
textField.text = [NSString stringWithFormat:@"(%@) ",num];
if (range.length > 0) {
[textField setText:[NSString stringWithFormat:@"%@",[num substringToIndex:3]]];
}
}
else if (length == 6) {
NSString *num = [self formatNumber:[textField text]];
[textField setText:[NSString stringWithFormat:@"(%@) %@-",[num substringToIndex:3],[num substringFromIndex:3]]];
if (range.length > 0) {
[textField setText:[NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]]];
}
}
return YES;
}
- (NSString*)formatNumber:(NSString*)mobileNumber {
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
int length = [mobileNumber length];
if (length > 10) {
mobileNumber = [mobileNumber substringFromIndex: length-10];
}
return mobileNumber;
}
Ответ 6
Для тех из вас, кто требует форматирования международного номера: https://code.google.com/p/libphonenumber/
Входит в реализацию С++, Java и JavaScript. Должно быть легко переносить реализации С++ в файл .mm и писать вокруг него небольшую обертку Objective-C.
Ответ 7
Возможно, вы могли бы использовать этот простой метод:
+ (NSString*) formatPhoneNumber:(NSString *)phoneNumber codeLength:(int) code segmentLength:(int) segment
{
NSString* result = @"";
int length = [phoneNumber length];
NSString* firstSegment = @"";
NSString* restSegment = @"";
for (int i=0; i<length; i++) {
char c = [phoneNumber characterAtIndex:i];
if(i < code)
firstSegment = [firstSegment stringByAppendingFormat:@"%c", c];
else
{
restSegment = [restSegment stringByAppendingFormat:@"%c", c];
int threshold = (i - code) + 1;
if((threshold % segment == 0) && (threshold > 0) && !(threshold > length))
restSegment = [restSegment stringByAppendingFormat:@"%c", '-'];
}
}
result = [result stringByAppendingFormat:@"%@-%@", firstSegment, restSegment];
return result;
}
Предполагая, что выше метод находится в классе Contact, просто используйте метод следующим образом:
NSString* phoneNumber = @"085755023455";
NSString* formattedNumber = [Contact formatPhoneNumber:phoneNumber codeLength:3 segmentLength:4];
Это приведет к чему-то вроде:
085-7550-2345-5
Ответ 8
Действительная опция https://github.com/iziz/libPhoneNumber-iOS Все остальные ответы охватывают только малую часть возможностей и комбинаций, эта библиотека фактически анализирует и проверяет КАЖДЫЙ номер телефона и идентифицирует:
- Национальность
- номер телефона
- Национальный перевозчик
Ответ 9
Соответствует номерам телефонов в США.
Добавляя к сообщению @wan, я добавил условный оператор, если пользователь начинает с кода страны (1). Таким образом, он будет выглядеть так: 1 (XXX) XXX-XXXX вместо (1XX) XXX-XXXX.
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{
textField = self.phoneNumberTextField;
NSInteger length = [self getLength:textField.text];
//NSLog(@"Length = %d ",length);
if ([textField.text hasPrefix:@"1"]) {
if(length == 11)
{
if(range.length == 0)
return NO;
}
if(length == 4)
{
NSString *num = [self formatNumber:textField.text];
textField.text = [NSString stringWithFormat:@"%@ (%@) ",[num substringToIndex:1],[num substringFromIndex:1]];
if(range.length > 0)
textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:4]];
}
else if(length == 7)
{
NSString *num = [self formatNumber:textField.text];
NSRange numRange = NSMakeRange(1, 3);
textField.text = [NSString stringWithFormat:@"%@ (%@) %@-",[num substringToIndex:1] ,[num substringWithRange:numRange],[num substringFromIndex:4]];
if(range.length > 0)
textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
}
} else {
if(length == 10)
{
if(range.length == 0)
return NO;
}
if(length == 3)
{
NSString *num = [self formatNumber:textField.text];
textField.text = [NSString stringWithFormat:@"(%@) ",num];
if(range.length > 0)
textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:3]];
}
else if(length == 6)
{
NSString *num = [self formatNumber:textField.text];
textField.text = [NSString stringWithFormat:@"(%@) %@-",[num substringToIndex:3],[num substringFromIndex:3]];
if(range.length > 0)
textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
}
}
return YES;
}
-(NSString*)formatNumber:(NSString*)mobileNumber
{
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
NSLog(@"%@", mobileNumber);
NSInteger length = [mobileNumber length];
if(length > 10)
{
mobileNumber = [mobileNumber substringFromIndex: length-10];
NSLog(@"%@", mobileNumber);
}
return mobileNumber;
}
-(NSInteger)getLength:(NSString*)mobileNumber
{
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
NSInteger length = [mobileNumber length];
return length;
}
Ответ 10
Вы можете использовать AKNumericFormatter библиотеку. Он имеет форматировщик и удобную категорию UITextField, он доступен как cocoapod.
Ответ 11
С# Xamarin.iOS версия наиболее полный ответ о том, как сделать форматирование телефона в iOS ниже
public override void ViewDidLoad()
{
base.ViewDidLoad();
PhoneNumberTextField.ShouldChangeCharacters = ChangeCharacters;
}
private bool ChangeCharacters(UITextField textField, NSRange range, string replacementString)
{
var text = textField.Text;
var newString = text.Substring(0, range.Location) + replacementString + text.Substring(range.Location + range.Length);
var decimalString = Regex.Replace(newString, @"[^\d]", string.Empty);
var length = decimalString.Length;
var hasLeadingOne = length > 0 && decimalString[0] == '1';
if ((length == 0) || (length > 10 && !hasLeadingOne) || (length > 11))
{
textField.Text = decimalString;
return false;
}
var index = 0;
var formattedString = "";
if (hasLeadingOne)
{
formattedString += "1";
index += 1;
}
if (length - index > 3)
{
var areaCode = decimalString.Substring(index, 3);
formattedString += "(" + areaCode + ")";
index += 3;
}
if (length - index > 3)
{
var prefix = decimalString.Substring(index, 3);
formattedString += " " + prefix + "-";
index += 3;
}
var remainder = decimalString.Substring(index);
formattedString += remainder;
textField.Text = formattedString;
return false;
}
Ответ 12
Быстрый форматированный номер телефона
Улучшает answer @datinc ответ,
вход, такой как 1123df#[email protected]$gdfg45-+678dfg901, будет выводиться как +11(234)567-8901
func formattedPhone(phone: String) -> String? {
let notPhoneNumbers = NSCharacterSet.decimalDigitCharacterSet().invertedSet
let str = phone.componentsSeparatedByCharactersInSet(notPhoneNumbers).joinWithSeparator("")
let startIdx = str.startIndex
let endIdx = str.endIndex
let count = str.characters.count
if count == 7 {
return "\(str[startIdx..<startIdx.advancedBy(3)])-\(str[startIdx.advancedBy(3)..<endIdx])"
}else if count == 10{
return "(\(str[startIdx..<startIdx.advancedBy(3)]))\(str[startIdx.advancedBy(3)..<startIdx.advancedBy(6)])-\(str[startIdx.advancedBy(6)..<endIdx])"
}
else if count > 10{
let extra = str.characters.count - 10
return "+\(str[startIdx..<startIdx.advancedBy(extra)])(\(str[endIdx.advancedBy(-10)..<endIdx.advancedBy(-7)]))\(str[endIdx.advancedBy(-7)..<endIdx.advancedBy(-4)])-\(str[endIdx.advancedBy(-4)..<endIdx])"
}
return nil
}
Ответ 13
NSString *[email protected]"[+]+91[0-9]{10}";
NSPredicate *no=[NSPredicate predicateWithFormat:@"SELF MATCHES %@",str];
if([no evaluateWithObject:txtMobileno.text]==NO
{
UIAlertView *alert=[[UIAlertView alloc]initWithTitle:@"Warning" message:@"Please Enter correct contact no." delegate:self cancelButtonTitle:@"ok" otherButtonTitles:nil];
[alert show];
[alert release];
}
Ответ 14
Итак, этот метод будет форматировать для (xxx) xxx - xxxx....
это модификация текущего верхнего ответа и обработка обратных пространств
- (IBAction)autoFormat:(UITextField *)sender {
NSString *mobileNumber = [NSString stringWithFormat:@"%@",sender.text];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
int length = [mobileNumber length];
if(length > 0 && [sender.text length] > self.oldLength){
if(length >= 7 && length <= 10){
sender.text = [NSString stringWithFormat:@"(%@) %@ - %@",[mobileNumber substringToIndex:3], [mobileNumber substringWithRange:NSMakeRange(3,3)],[mobileNumber substringWithRange:NSMakeRange(6,[mobileNumber length]-6)]];
} else if(length >= 4 && length <= 6) {
sender.text = [NSString stringWithFormat:@"(%@) %@",[mobileNumber substringToIndex:3], [mobileNumber substringWithRange:NSMakeRange(3,[mobileNumber length]-3)]];
}
if(length >= 11 && length % 4 == 3){
NSString *lastChar = [sender.text substringFromIndex:[sender.text length] - 1];
sender.text = [NSString stringWithFormat:@"%@ %@",[sender.text substringToIndex:[sender.text length] - 1],lastChar];
}
self.oldLength = [sender.text length];
} else if([sender.text length] < self.oldLength) {
NSLog(@"deleted - ");
self.oldLength = 0;
sender.text = @"";
for (int i = 0; i < [mobileNumber length]; i = i + 1) {
sender.text = [NSString stringWithFormat:@"%@%@",sender.text,[mobileNumber substringWithRange:NSMakeRange(i, 1)]];
[self autoFormat:sender];
}
}}
надеюсь, что это поможет
Ответ 15
REFormattedNumberField, вероятно, лучший. Просто поставьте желаемый формат.
Ответ 16
Также для формата + x (xxx) xxx-xx-xx вы можете использовать что-то вроде этого простого решения:
+ (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
NSString *newString = [textField.text stringByReplacingCharactersInRange:range withString:string];
NSArray *components = [newString componentsSeparatedByCharactersInSet:[[NSCharacterSet decimalDigitCharacterSet] invertedSet]];
NSString *decimalString = [components componentsJoinedByString:@""];
if (decimalString.length > 11) {
return NO;
}
NSMutableString *formattedString = [NSMutableString stringWithString:decimalString];
[formattedString insertString:@"+" atIndex:0];
if (formattedString.length > 2)
[formattedString insertString:@" (" atIndex:2];
if (formattedString.length > 7)
[formattedString insertString:@") " atIndex:7];
if (formattedString.length > 12)
[formattedString insertString:@"-" atIndex:12];
if (formattedString.length > 15)
[formattedString insertString:@"-" atIndex:15];
textField.text = formattedString;
return NO;}
Ответ 17
SWIFT
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
let length = self.getTextLength(textField.text)
if length == 10{
if range.length == 0{
return false
}
}
if length == 3{
var num : String = self.formatNumber(textField.text)
textField.text = num + "-"
if(range.length > 0){
textField.text = (num as NSString).substringToIndex(3)
}
}
else if length == 6{
var num : String = self.formatNumber(textField.text)
let prefix = (num as NSString).substringToIndex(3)
let postfix = (num as NSString).substringFromIndex(3)
textField.text = prefix + "-" + postfix + "-"
if range.length > 0{
textField.text = prefix + postfix
}
}
return true
}
func getTextLength(mobileNo: String) -> NSInteger{
var str : NSString = mobileNo as NSString
str = str.stringByReplacingOccurrencesOfString("(", withString: "")
str = str.stringByReplacingOccurrencesOfString(")", withString: "")
str = str.stringByReplacingOccurrencesOfString(" ", withString: "")
str = str.stringByReplacingOccurrencesOfString("-", withString: "")
str = str.stringByReplacingOccurrencesOfString("+", withString: "")
return str.length
}
func formatNumber(mobileNo: String) -> String{
var str : NSString = mobileNo as NSString
str = str.stringByReplacingOccurrencesOfString("(", withString: "")
str = str.stringByReplacingOccurrencesOfString(")", withString: "")
str = str.stringByReplacingOccurrencesOfString(" ", withString: "")
str = str.stringByReplacingOccurrencesOfString("-", withString: "")
str = str.stringByReplacingOccurrencesOfString("+", withString: "")
if str.length > 10{
str = str.substringFromIndex(str.length - 10)
}
return str as String
}
Ответ 18
+(NSString *) phoneNumberFormatterTextField:(NSString *)number forRange:(NSRange)range
{
int length = (int)[[self getPhoneNumber:number] length];
if(length == 3)
{
NSString *num = [MPosBaseScreenController getPhoneNumber:number];
number = [num stringByReplacingOccurrencesOfString:@"(\\d{3})"
withString:@"($1) "
options:NSRegularExpressionSearch
range:NSMakeRange(0, num.length)];
}
else if(length == 6 || length > 6 )
{
NSString *num = [MPosBaseScreenController getPhoneNumber:number];
number = [num stringByReplacingOccurrencesOfString:@"(\\d{3})(\\d{3})"
withString:@"($1) $2 - "
options:NSRegularExpressionSearch
range:NSMakeRange(0, num.length)];
}
return number;
}
Ответ 19
Здесь простая категория, которая будет имитировать формат ввода
@interface NSString (formatDecimalsAs)
- (NSString *)formatDecimalsAs:(NSString *)formattedDecimals;
@end
@implementation NSString (formatDecimalsAs)
- (NSString *)formatDecimalsAs:(NSString *)formattedDecimals
{
// insert non-digit characters from source string
NSMutableString *formattedNumber = [self mutableCopy];
for (int i = 0; i < formattedDecimals.length; i++)
{
if (i > formattedNumber.length)
{
break;
}
unichar character = [formattedDecimals characterAtIndex:i];
if ([[NSCharacterSet decimalDigitCharacterSet].invertedSet characterIsMember:character])
{
[formattedNumber insertString:[NSString stringWithFormat:@"%c", character] atIndex:(NSUInteger) i];
}
}
return formattedNumber;
}
@end
Пример использования
[@"87654321" formatDecimalsAs:@"1111 1111"] // returns @"8765 4321"
Ответ 20
- Удаляет все нецифровые символы
- Если осталось 7 цифр, 123-4567
- для 10 цифр, (123) 456-7890
-
В противном случае, группы из трех. Чтобы настроить размер групп, измените значение, назначенное для substrsize
-(NSString*)formatPhone:(NSString*)phone { NSString *formattedNumber = [[phone componentsSeparatedByCharactersInSet: [[NSCharacterSet decimalDigitCharacterSet] invertedSet]] componentsJoinedByString:@""]; int substrSize = 3; NSMutableArray *t = [[NSMutableArray alloc] initWithCapacity:formattedNumber.length / substrSize + 1]; switch (formattedNumber.length) { case 7: formattedNumber = [NSString stringWithFormat:@"%@-%@", [formattedNumber substringToIndex:3], [formattedNumber substringFromIndex:3]]; break; case 10: formattedNumber = [NSString stringWithFormat:@"(%@) %@-%@", [formattedNumber substringToIndex:3], [formattedNumber substringWithRange:NSMakeRange(3, 3)], [formattedNumber substringFromIndex:6]]; break; default: for (int i = 0; i < formattedNumber.length / substrSize; i++) { [t addObject:[formattedNumber substringWithRange:NSMakeRange(i * substrSize, substrSize)]]; } if (formattedNumber.length % substrSize) { [t addObject:[formattedNumber substringFromIndex:(substrSize * t.count)]]; } formattedNumber = [t componentsJoinedByString:@" "]; break; } return formattedNumber; }
Ответ 21
В SWIFT 3
func formattedPhone(phone: String) -> String? {
let notPhoneNumbers = CharacterSet.decimalDigits.inverted
let str = phone.components(separatedBy: notPhoneNumbers).joined(separator: "")
let startIdx = str.startIndex
let endIdx = str.endIndex
let count = str.characters.count
if count == 7 {
return "\(str[startIdx..<startIdx.advance(3, for: str)])-\(str[startIdx.advance(3, for: str)..<endIdx])"
}else if count == 10{
return "+1 (\(str[startIdx..<startIdx.advance(3, for: str)])) \(str[startIdx.advance(3, for: str)..<startIdx.advance(6, for: str)])-\(str[startIdx.advance(6, for: str)..<endIdx])"
}
else if count > 10{
let extra = str.characters.count - 10
return "+\(str[startIdx..<startIdx.advance(extra, for: str)]) (\(str[endIdx.advance(-10, for: str)..<endIdx.advance(-7, for: str)])) \(str[endIdx.advance(-7, for: str)..<endIdx.advance(-4, for: str)])-\(str[endIdx.advance(-4, for: str)..<endIdx])"
}
return nil
}
Swift 3 string.index.advancedBy(3) alternate:
extension String.Index{
func advance(_ offset:Int, `for` string:String)->String.Index{
return string.index(self, offsetBy: offset)
}
}
Ответ 22
Это поможет вам
Формат (xxx) xxx-xxxx Для SWIFT 3.0
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
let length = Int(getLength(mobileNumber: textField.text!))
if length == 15 {
if range.length == 0 {
return false
}
}
if length == 3 {
let num = self.formatNumber(mobileNumber: textField.text!)
textField.text = NSString(format:"(%@)",num) as String
if range.length > 0{
let index: String.Index = num.index(num.startIndex, offsetBy: 3)
textField.text = NSString(format:"%@",num.substring(to: index)) as String
}
}else if length == 6 {
let num = self.formatNumber(mobileNumber: textField.text!)
let index: String.Index = num.index(num.startIndex, offsetBy: 3)
textField.text = NSString(format:"(%@) %@-",num.substring(to: index), num.substring(from: index)) as String
if range.length > 0{
textField.text = NSString(format:"(%@) %@",num.substring(to: index), num.substring(from: index)) as String
}
}
return true
}
func formatNumber(mobileNumber: String) -> String {
var number = mobileNumber
number = number.replacingOccurrences(of: "(", with: "")
number = number.replacingOccurrences(of: ")", with: "")
number = number.replacingOccurrences(of: " ", with: "")
number = number.replacingOccurrences(of: "-", with: "")
number = number.replacingOccurrences(of: "+", with: "")
let length = Int(number.characters.count)
if length > 15 {
let index = number.index(number.startIndex, offsetBy: 15)
number = number.substring(to: index)
}
return number
}
func getLength(mobileNumber: String) -> Int {
var number = mobileNumber
number = number.replacingOccurrences(of: "(", with: "")
number = number.replacingOccurrences(of: ")", with: "")
number = number.replacingOccurrences(of: " ", with: "")
number = number.replacingOccurrences(of: "-", with: "")
number = number.replacingOccurrences(of: "+", with: "")
let length = Int(number.characters.count)
return length
}
Ответ 23
Сначала добавьте UITextFieldDelegate в ваш .h файл и делегируйте свой UITextField в файл nib.
Во-вторых, добавьте этот код в свой .m файл:
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
NSString *filter = @"(###)-(###)-####";
if(!filter) return YES;
NSString *changedString = [textField.text stringByReplacingCharactersInRange:range withString:string];
if(range.length == 1 &&
string.length < range.length &&
[[textField.text substringWithRange:range] rangeOfCharacterFromSet:[NSCharacterSet characterSetWithCharactersInString:@"0123456789"]].location == NSNotFound)
{
NSInteger location = changedString.length-1;
if(location > 0)
{
for(; location > 0; location--)
{
if(isdigit([changedString characterAtIndex:location]))
{
break;
}
}
changedString = [changedString substringToIndex:location];
}
}
textField.text = [self filteredPhoneStringFromStringWithFilter:changedString :filter];
return NO;
}
-(NSString*) filteredPhoneStringFromStringWithFilter:(NSString*)number : (NSString*)filter{
NSUInteger onOriginal = 0, onFilter = 0, onOutput = 0;
char outputString[([filter length])];
BOOL done = NO;
while(onFilter < [filter length] && !done)
{
char filterChar = [filter characterAtIndex:onFilter];
char originalChar = onOriginal >= number.length ? '\0' : [number characterAtIndex:onOriginal];
switch (filterChar) {
case '#':
if(originalChar=='\0')
{
// We have no more input numbers for the filter. We're done.
done = YES;
break;
}
if(isdigit(originalChar))
{
outputString[onOutput] = originalChar;
onOriginal++;
onFilter++;
onOutput++;
}
else
{
onOriginal++;
}
break;
default:
// Any other character will automatically be inserted for the user as they type (spaces, - etc..) or deleted as they delete if there are more numbers to come.
outputString[onOutput] = filterChar;
onOutput++;
onFilter++;
if(originalChar == filterChar)
onOriginal++;
break;
}
}
outputString[onOutput] = '\0'; // Cap the output string
return [NSString stringWithUTF8String:outputString];
}