код:
#include <functional>
struct Foo
{
virtual void mf() = 0;
};
struct Bar: Foo
{
virtual void mf() {}
};
int main()
{
Bar o;
std::reference_wrapper<Foo const> wrapper( o );
}
Результат с MinGW g++ 4.6.1:
[d:\dev\test] > g++ foo.cpp -std=c++0x [d:\dev\test] > _
Результат с Visual С++ 10.0:
[d:\dev\test] > cl foo.cpp foo.cpp C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xrefwrap(371) : see reference to class template instantiation 'std::tr1::_Call_wrapper' being compiled with [ _Callable=std::tr1::_Callable_obj ] C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xrefwrap(416) : see reference to class template instantiation 'std::tr1::_Refwrap_impl' being compiled with [ _Ty=const Foo ] foo.cpp(16) : see reference to class template instantiation 'std::tr1::reference_wrapper' being compiled with [ _Ty=const Foo ] C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2027: use of undefined type 'std:: tr1::_Result_of' with [ _Ty=const Foo (void) ] C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(9) : error C2143: syntax error : missing ';' before '(' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(9) : error C4430: missing type specifier - int assumed. Note: C++ does not support default-int C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(10) : error C4430: missing type specifier - int assumed. Note: C++ does not support default-int C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\xxcallwrap(8) : error C2259: 'Foo' : cannot instantiate abstract class due to following members: 'void Foo::mf(void)' : is abstract foo.cpp(5) : see declaration of 'Foo::mf' [d:\dev\test] > _
Мне нравится, как компилятор Visual С++ сообщает пользователю 11 раз, что абстрактный класс не может быть создан, просто чтобы забить точку дома, например, в случае, если пользователь не знал об этом. Но должен ли std::reference_wrapper
создать экземпляр класса? Не значительная часть ссылки (прохождение) не требует создания экземпляра?
I.e., это, как я подозреваю, ошибка в реализации стандартной библиотеки Visual С++?